Compare the Triplets | Hacker Rank Solution using Java 7

Problem :

Alice and Bob each created one problem for HackerRank. A reviewer rates the two challenges, awarding points on a scale from 1 to 100 for three categories: problem clarity, originality, and difficulty.

The rating for Alice's challenge is the triplet a = (a[0], a[1], a[2]), and the rating for Bob's challenge is the triplet b = (b[0], b[1], b[2]).

The task is to find their comparison points by comparing a[0] with b[0], a[1] with b[1], and a[2] with b[2].

  • If a[i] > b[i], then Alice is awarded 1 point.
  • If a[i] < b[i], then Bob is awarded 1 point.
  • If a[i] = b[i], then neither person receives a point.

Comparison points is the total points a person earned.

Given a and b, determine their respective comparison points.

Example

a = [1, 2, 3]
b = [3, 2, 1]

  • For elements *0*, Bob is awarded a point because a[0] .
  • For the equal elements a[1] and b[1], no points are earned.
  • Finally, for elements 2, a[2] > b[2] so Alice receives a point.

The return array is [1, 1] with Alice's score first and Bob's second.


Solution:

import java.io.*;
import java.util.*;  
public class Solution {
    public static void main(String[] args) throws IOException {
        int a[] = new int[3];
        Scanner scan=new Scanner(System.in);
        for (int i = 0; i < 3; i++) {
            a[i]=scan.nextInt();         
        }
        int b[]=new int[3];
        for (int i = 0; i < 3; i++) {
            b[i]=scan.nextInt();         
        }

        int al=0;
        int bo=0;       
for(int i=0;i<3;i++)
{
    if(a[i]>b[i])
    {
         al++;
    }
    else if(a[i]<b[i])
    {
        bo++;
    }
    else 
    {

    }
}
System.out.print(al+" "+bo);
  }
}

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